OMG! That's why beer makes you drunk! Will be watching this one from behind the couch, Pim.

Haha, really defines the gender gap doesn't it.

From elsewhere. Not edited (copied and pasted as-is).

The Gravitational Exchange Tachyon (GET)

If, for any function F , we can define derivatives with respect to x , so that
F(x) = f'(x) = df(x) / d(x) , then, for functions f and F , we can give a definite integral between positive and negative infinity, for the variable x , equal to the sum of the integrals that take negative and positive infinity separately.
If we let x be the time t , then the positive integral can be used for studying bradyons, with positive time, and the negative for tachyons, with negative time.
And imposing exclusivity on the two time integrals, to remove absolute-zero and infinite-velocity solutions, pertinent parameters corresponding to each type of particle (bradyons, photons, and tachyons) are rendered empirical.

That said, the functional operator a , used to impose Einsteinian relativity on an object of rest-mass m , is given as a function of the ratio between the velocity...

[ Continued ]

The Tachyonics Operator and the Velocity Spectrum

The traditional method of describing a tachyon is to take the result of inputting a superluminal velocity in the formula for the Relativity Operator (alpha), and using a negatively-signed but otherwise standard imaginary-unit, i , to express the result. That is, if mr is a real mass, then an imaginary mass m , for a tachyon, can be obtained as a direct analog of the real mass, by writing; m = -imr . [Reference:
Encyclopedia of Physics, 2nd Ed., by Lerner & Trigg, VCH Publishing, pg. 1246.]
However, due to the implication that there exists a superluminal universe, we can imagine that it exhibits its own number system, incompatible with the standard number system (although, there is a one-to-one correspondence). In that case, the standard imaginary-unit ( i = sqrt (-1) ; i^2 = -1 ) becomes inadequate to describe the kind of tachyon I wish to employ to explain quantum gravity (though the traditional method works fine...

[ Continued ]